// C++ program to find the largest subtree
// having identical left and right subtree
#include <bits/stdc++.h>
using namespace std;
/* Shows a binary tree node has data, pointer to left
child and a pointer to right child */
struct Node1{
int data1;
Node1* left1, * right1;
};
/* Shows helper function that allocates a new node with
the given data and NULL left and right pointers. */
Node1* newNode(int data1){
Node1* node1 = new Node1;
node1->data1 = data1;
node1->left1 = node1->right1 = NULL;
return (node1);
}
// Used to set maxSize to size of largest subtree with
// identical left and right. maxSize is set with
// size of the maximum sized subtree. It returns
// size of subtree rooted with current node. This
// size is used to keep track of maximum size.
int largestSubtreeUtil(Node1* root1, string& str1,
int& maxSize, Node1*& maxNode){
if (root1 == NULL)
return 0;
// Uses string to store structure of left and
// right subtrees
string left1 = "", right1 = "";
// Visit left subtree and finds its size
int ls1 = largestSubtreeUtil(root1->left1, left1,maxSize, maxNode);
// Visit right subtree and finds its size
int rs1 = largestSubtreeUtil(root1->right1, right1,maxSize, maxNode);
// if left and right subtrees are similar
// update maximum subtree if needed (Note that
// left subtree may have a bigger value than
// right and vice versa)
int size1 = ls1 + rs1 + 1;
if (left1.compare(right1) == 0){
if (size1 > maxSize){
maxSize = size1;
maxNode = root1;
}
}
//Used to append left subtree data
str1.append("|").append(left1).append("|");
// Used to append current node data
str1.append("|").append(to_string(root1->data1)).append("|");
// Used to append right subtree data
str1.append("|").append(right1).append("|");
return size1;
}
// Shows function to find the largest subtree
// having identical left and right subtree
int largestSubtree(Node1* node1, Node1*& maxNode){
int maxSize = 0;
string str1 = "";
largestSubtreeUtil(node1, str1, maxSize, maxNode);
return maxSize;
}
/* Driver program to test above functions*/
int main(){
/* Let us construct the following Tree
55
/ \
15 70
/ \ / \
10 25 75 75
/ \ / \
70 85 70 85 */
Node1* root1 = newNode(55);
root1->left1 = newNode(15);
root1->right1 = newNode(70);
root1->left1->left1 = newNode(10);
root1->left1->right1 = newNode(25);
root1->right1->left1 = newNode(75);
root1->right1->left1->left1 = newNode(70);
root1->right1->left1->right1 = newNode(85);
root1->right1->right1 = newNode(75);
root1->right1->right1->left1 = newNode(70);
root1->right1->right1->right1 = newNode(85);
Node1 *maxNode = NULL;
int maxSize = largestSubtree(root1, maxNode);
cout << "Largest Subtree is rooted at node "
<< maxNode->data1 << "\nand its size is "
<< maxSize;
return 0;
}
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